So the coefficient of the disc braking surface is dictated by the tire coefficient?
That was my question. I was unsure if the increased grip at the tire always provided enough drive at the disc to prevent lock up earlier than the tire can handle.
Ill try to explain what I meant previously.
The pads and disc have their own coefficient.
The wheel and the ground as its coefficient.
My thinking was that when you add weight to the bike you increase the coefficient at the tire. This also increases the drive through he disc brake, more grip equals more force pushing the disc through the pads under braking.
I than was asking, if at any point does the increase in grip at the tire not match the increased drive through the disc and thereby the coefficient at the disc is not increased as much as it is at the tire. Resulting in a brake that will lock up before the tire is ready, thereby locking the wheel before the coefficient is reached at the tire.
That make anymore sense?
After thinking about this more, I realized that this situation would mean that the bike would stop dead in its tracks. As you could effectively lock the brake without breaking traction.
I guess what I was thinking along the lines of initially was actually a situation where the brake would have poor modulation and the bite point would jump up. Say we can only brake in 50lbs increments and the the tire breaks at 630, the 30lbs of traction would be lost as going to 650 would break traction, this however is just a classic case of brakes been more powerful than the tire as the lock up point is still higher than the tire. Its just inefficient braking at 600lbs.
This is very interesting but I have to disagree with point (a) that skidding is losing control
I think most would agree but we are not referring to riding but braking forces. Skidding is not effective for braking and represents a loss of braking control.